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With setTimeOut, why it console 4, 5 times ? javascript

If I run this code then it console 4 at 5 time, can anyone explain why it is happening ?

let number = 1;

for (var i=0; i<5; i++){
  number=i;
  setTimeout(()=>{
    console.log(number)
  },1000)
}

Also if I modify this to as below then output is 5 times 5 ?

for (var i=0; i<5; i++){
  setTimeout(()=>{
    console.log(i)
   },1000)
 }

And why it prints 0 to 4 when we use let like

    for (let i=0; i<5; i++){
  setTimeout(()=>{
    console.log(i)
   },1000)
 }
about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

Its a typical use case of var being functional scope ,every iteration of for loop shares the same value of var (doesn't creates a new scope as var being functional scope) which is kind of global in here

so when the last condition arrives i<5 i is already has become 4 ,and it is shared by every callback of setTimeout so they all prints 4 ,4 times

But in case of let a new scope is formed in every iteration ,as let being a block scope (for loop has a block scope)

about 4 years ago · Juan Pablo Isaza Report
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