Tengo una variedad de productos con un rango de precios "desde, hasta"
const goods = [ { name: "Sweets", prices: [0, 100] }, { name: "Chocolate", prices: [500, null] }, { name: "Cheesecake", prices: [100, 200] }, { name: "Truffle", prices: [null, null] }, { name: "Apple cake", prices: [null, 400] }, { name: "Banana cake", prices: [50, 250] }, { name: "Raspberry cake", prices: [200, null] }, { name: "Donuts", prices: [51, 450] }, , ]; para filtrarlos con las opciones requeridas donde null en tupla [null, 200] significa que el precio máximo del producto es 200 y [200, null] significa que el precio mínimo del producto es 200.
const requiredRange1 = [null, 200]; const requiredRange2 = [100, 350]; const requiredRange3 = [200, null]; const requiredRange4 = [200, 300]; const requiredRange5 = [1000, null]; por ejemplo: la salida de requiredRange1 es
[ { name: "Sweets", prices: [0, 100] }, { name: "Cheesecake", prices: [100, 200] }, { name: "Apple cake", prices: [null, 400] }, { name: "Banana cake", prices: [50, 250] }, { name: "Raspberry cake", prices: [200, null] }, { name: "Donuts", prices: [51, 450] }, ]Escribí una función
const filterCourses = (arrayOfCourses, requiredRange) => { const [minRequiredPrice, maxRequiredPrice] = requiredRange; const filterCallback = (course) => { const maxCoursePrice = course.prices[1]; const minCoursePrice = course.prices[0]; if(minCoursePrice === null && maxCoursePrice === null) { return false } if(minRequiredPrice === null) { return maxRequiredPrice >= minCoursePrice } else if(maxRequiredPrice === null) { return minRequiredPrice <= maxCoursePrice || minCoursePrice >= minRequiredPrice } else { return (minRequiredPrice > maxCoursePrice && maxCoursePrice !== null) || (maxRequiredPrice < minCoursePrice && minCoursePrice !== null) ? false : true } } const result = arrayOfCourses.filter(filterCallback) return result }Parece bastante codificado, ¿cómo puedo filtrar esta matriz de una manera más elegante?
Mas elegante:
function doRangesIntersect(a, b) { const lo = Math.max(a[0] ?? -Infinity, b[0] ?? -Infinity); const hi = Math.min(a[1] ?? Infinity, b[1] ?? Infinity); return lo <= hi; } function filterCourses(arrayOfCourses, requiredRange) { return arrayOfCourses.filter(course => doRangesIntersect(course.prices, requiredRange)); }