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|| operator in arguments

I have an issue:

    //this console log displays correct value
    console.log('localstorage', localStorage.getItem('subMenu'));
    
    setSubMenu(
      JSON.parse(localStorage.getItem('subMenu') || JSON.stringify(subMenu))
    );
    /*
    this one displays JSON.stringify(subMenu) value, when 
    localStorage.getItem('subMenu') is defined 
    */
    console.log('subMenu', subMenu);

I have no idea what's happening. there is value in localstorage (checked with console logs), but somehow JSON.parse is reading second value.

about 4 years ago · Santiago Gelvez
1 answers
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0

|| is or operator ... if the result is those bellow,references the one on the right

  • undefined
  • false
  • 0
  • '' or null

for example

 let a=null || 45;  //a=45
 let b=12 || 45;  //a=12
about 4 years ago · Santiago Gelvez Report
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