this is my code :
var num = parseInt(105);
// debugger
if (num < 1) {
console.log("=> 0 or minus value is not a prime number", num);
} else if (num == 2) {
console.log("=> 2 is a prime number", num);
} else if (num > 2) {
for (i = 2; i < num; i++) {
if (num % i == 0) {
console.log("this is a not prime number as it is devided by zero");
break
} else {
console.log("this is a prime number")
}
}
}in this code why else statement is showing the output when I put any odd numbers where I already worte the break statement for stopping the loop break.
If the number is not divisible by a particular i then your else condition is being executed. Change num to 5 you would see this is a prime number print several times.
You can create a function (as shown below) where we first check all the is then print this is a prime number.
function isPrime(num) {
if (num < 1) {
console.log("=> 0 or negative values are not prime numbers", num);
} else if (num === 2) {
console.log("=> 2 is a prime number", num);
} else if (num > 2) {
for (let i = 2; i < num; i++) {
if (num % i === 0) {
console.log(`this is a not prime number as it is divisible by ${i}`);
return;
}
}
}
console.log("this is a prime number");
}
isPrime(105);Or you can store the result in a variable, and at the end of the loop print this is a prime number if the variable wasn't set.
const num = 105;
if (num < 1) {
console.log("=> 0 or negative values are not prime numbers", num);
} else if (num === 2) {
console.log("=> 2 is a prime number", num);
} else if (num > 2) {
let isPrime;
for (let i = 2; i < num; i++) {
if (num % i === 0) {
console.log(`this is a not prime number as it is divisible by ${i}`);
isPrime = false;
break;
}
}
if (isPrime !== false) {
console.log("this is a prime number");
}
}