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Why Typescript doesn't fail when spreading a function?

Having a typescript piece of code like the following:

const f = () => {}
const o = { ...f }
// o === {}

Why doesn't TS complain about spreading a function? I would expect this to be ok in plain javascript (since functions are objects in the end) but I don't understand why TS allows this (does it make any sense for a function to be iterable?)

about 4 years ago · Juan Pablo Isaza
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