What is the best way to add optional filters based on a condition? For instance, consider the following code fragment:
<Menu>
{itemGroupLevels.map(group) = [
this.props.itemTypes
.filter((x) => x.group_level === group)
.filter((x) => x.article_type_code !== "GRAL")
{Permission.TEACHER?filter((x) => !x.article_type_code.includes('BACKPACK','LUNCH')):null}
.map((value) => (
])}
</Menu>
How can I add the last filter depending on a condition such as if the user has specific permission to avoid including BACKPACK and LUNCH just if the user is a teacher:
{Permission.TEACHER?filter((x) => !x.article_type_code.includes('BACKPACK','LUNCH')):null}
Otherwise, I do not need to add the filter and just leave the two previous filters.
Thanks for your help
Add an if condition within the filter... this ensures that if the user does not have the proper permissions the filter will not return any values.
<Menu>
{itemGroupLevels.map(group) = [
this.props.itemTypes
.filter((x) => x.group_level === group)
.filter((x) => x.article_type_code !== "GRAL")
.filter((x) => {
if (!Permission.TEACHER) return true
return !x.article_type_code.includes('BACKPACK','LUNCH')
})
.map((value) => (
])}
</Menu>
Instead of stacking separate filter() calls, it would be better to move the business logic out into a separate function and filter once. This also means you'll avoid looping over the data multiple times for filtering.
const filterGroupItemTypes = (group, item) => {
return (
item.group_level === group &&
item.article_type_code !== "GRAL" &&
// TODO: Implement
(Permission.TEACHER ? ... : true)
);
};
And then in your renderer
this.props.itemTypes.filter((item) => filterGroupItemTypes(group, item)).map(...)