I have this array:
[
{
"id": "z12",
"val": "lu",
"val2": "1",
},
{
"id": "z13",
"val": "la",
"val2": "2",
},
{
"id": "z14",
"val": "lo",
"val2": "3",
},
]
I have second
array2 = {
tab: [],
}
i do in my typeScript :
array.forEach((item, index)=>{
if(item.id === z12){
array.splice(index, 1);
}else{
array2.tab.push(item.id);
}
});
I should normally have: tab: [z13,z14] but it does not work
You can filter and map directly.
const array = [{ "id": "z12", "val": "lu", "val2": "1", }, { "id": "z13", "val": "la", "val2": "2", }, { "id": "z14", "val": "lo", "val2": "3", },];
const array2 = {
tab: array.filter(e => e['id'] != "z12").map(e => e['id']),
}
console.log(array2)I think you could make it in two steps:
// first remove the "z12" from the array as you requested
array = array.filter(e => e.id !== 'z12')
// and second get the remaining ids
array2 = {
tab: array.map(e => e.id)
}
splice() method in forEach() cause the problem when the "z12" was removed, the array became
[
{
"id": "z13",
"val": "la",
"val2": "2",
},
{
"id": "z14",
"val": "lo",
"val2": "3",
},
]
BUT the iteration of forEach method did not stop itself. it will continue with index of 1 that just after the z12 was removed so the index of 1 is the "z14", not the "z13".
some knowledge of forEach forEach is BAD!