My changelog.md data looks like below.
## 11.2.3
* xxx
* xxxx
## 11.2.2
* ttt
* ttt
I need a regex that can return only the first versions list ie.
* xxx
* xxxx
I tried multiple solutions but, didn't reach the final result.
I tried matching, and replacing it, didn't work.
const changelog = `
## Hello World
* This is a bold text
* This is a bold text
## Hello World
* This is a bold text
## Hello World
* This is a bold text
`;
const final = changelog.match( /([^(##)])(.*)[^(##)]/g );
console.log(final);You don't need to put ^## inside []. Square brackets are for making character sets, () is for grouping. There's no need to group it if you're not interested in that part.
Use the m modifier to make ^ match the beginning of a line instead of the the beginning of the string. Then .*\n will match the rest of that line. [^#]* will match everything after that until the next #.
const changelog = `
## Hello World
* This is a bold text
* This is a bold text
## Hello World
* This is a bold text
## Hello World
* This is a bold text
`;
const final = changelog.match(/^##.*\n([^#]*)/m);
console.log(final[1]);