The following code works but is slow because I need to await each response instead of asynchronously processing the responses as they come in.
I imagine there is a way to do this with promises.all() but can't come up with a solution.
let relatives = [ancestor];
while (relatives.length > 0) {
const nextRelative = relatives.pop();
await fetchRelatives(nextRelative).then(relative => {
relatives = relatives.concat(relative.ancestors);
});
}
We can assume the order is not important, as long as we process the entire tree.
You can use promises:
Promise.all( relatives.map( task => fetchRelatives(task) ) ).then( results => {
console.log('all responses:', results)
})
Or
var results = await Promise.all( relatives.map( task => fetchRelatives(task) ) )
if relatives is added dynamically, then this should work:
var do_task = async( relative ) => {
if (relative)
relatives.push(... relative.ancestors)
if (relatives.length)
return fetchRelatives( relatives.pop() ).then( person => do_task( person ) )
}
/// 4 workers:
Promise.all( Array(4).fill().map( do_task ) ).then(() => console.log('all done'))
if The order of the answers is important to you. You have no choice but to use the async/await or generator functions.