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¿Cómo encontrar múltiples <br> en secuencia a través de document.querySelector?

Si tengo una secuencia de varios <br> , ¿cómo puedo mostrar cuántas secuencias tengo?

En otras palabras, estoy tratando de contar cuántas veces tuvimos <br><br> como en dos
s seguidos.

 // Undesired output: console.log(document.querySelectorAll('br').length) // 8 console.log(document.querySelectorAll('br+br').length) // 7
 <div id="test"> Paragraph 1 <br> <br> Paragraph 2 <br>Paragraph 2 continued <br> <br> Paragraph 3 <br>Paragraph 3 continued <br> <br> Paragraph 4 </div>

Salida deseada:

 console.log(document.querySelectorAll('?????').length) // 3
about 4 years ago · Juan Pablo Isaza
3 answers
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0

Puede usar expresiones regulares para encontrar <br><br> s:

 var p = /<br>[\r\n]*<br>/g; console.log([...document.querySelector('#test').innerHTML.matchAll(p)].length); // => 3
 <div id="test"> Paragraph 1 <br> <br> Paragraph 2 <br>Paragraph 2 continued <br> <br> Paragraph 3 <br>Paragraph 3 continued <br> <br> Paragraph 4 </div>

about 4 years ago · Juan Pablo Isaza Report

0

prueba esto:

 var nodes = document.querySelectorAll('br, div'); console.log(nodes);
 <div id="test"> Paragraph 1 <br> <br> Paragraph 2 <br>Paragraph 2 continued <br> <br> Paragraph 3 <br>Paragraph 3 continued <br> <br> Paragraph 4 </div>

about 4 years ago · Juan Pablo Isaza Report

0

No pude pensar en una mejor manera de hacerlo, ¡espero que esto ayude!

 const brTags = document.querySelectorAll('br') let tagCount = 0; for(let i = 0; i < brTags.length; i++){ const string = brTags[i].nextSibling.textContent .replaceAll("\n", "") .trim(); if(string.indexOf("Paragraph") > -1 && string.length === 11){tagCount++} } console.log ("Tag count: ", tagCount);
 <div id="test"> Paragraph 1 <br> <br> Paragraph 2 <br>Paragraph 2 continued <br> <br> Paragraph 3 <br>Paragraph 3 continued <br> <br> Paragraph 4 </div>

about 4 years ago · Juan Pablo Isaza Report
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