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int() argument must be a string, a bytes-like object or a number, not 'generator' django

Tengo el siguiente error como puedo solucionarlo ?

el modelo es:

class myModel(models.Model):
    name = models.CharField(max_length=50)
    libraries = models.ManyToManyField(library)

y en el endpoint así:

new_obj = myModel.objects.create(name=name)
my_obj.libraries.add(Library.objects.filter(pk=l.pk) for l in input_libraries.get('libraries'))

over 4 years ago · Santiago Trujillo
1 answers
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Estas intentando guardar un generador en un add que es para adicionar un solo elemento.

Un objeto generador en python es algo así como una lista perezosa. Los elementos solo se evalúan tan pronto como itera sobre ellos.

entonces para resolverlo usa set()

my_obj.libraries.set(Library.objects.filter(pk=l.pk) for l in input_libraries.get('libraries'))
over 4 years ago · Santiago Trujillo Report
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