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analizando etiquetas duplicadas en xml javascript

Escribí el código a continuación para obtener básicamente los datos de 'punto' e imprimirlos, por lo que si selecciono el nombre de etiqueta 'punto', está imprimiendo todas las coordenadas en la etiqueta.

Pero quiero analizar cada etiqueta de 'puntos' en un bucle for de modo que la primera iteración del bucle imprima todas las coordenadas desde la primera etiqueta de 'puntos' y la segunda iteración imprima las coordenadas desde la segunda etiqueta de 'puntos' y así sucesivamente ,

y escribí el código en consecuencia, pero no me consuela nada, incluso probé .eq() y el enésimo hijo, pero el problema es que tengo varias etiquetas de 'puntos'

...

 <object> <coordinate>pixel</coordinate> <type>rectangle</type> <description>None</description> <possibleresult> <name>Intersection</name> </possibleresult> <points> <point>684.999939,182.999985</point> <point>682.568420,217.040604</point> <point>612.568420,212.040604</point> </points> </object>

...

...

 fetch("file.xml") .then(response => response.text()) .then(data => { var txt; txt=""; const parser = new DOMParser(); const xml = parser.parseFromString(data, "application/xml"); console.log(xml); x = xml.getElementsByTagName("points point"); for (i = 0; i< x.length; i++) { txt += x[i].childNodes[0].nodeValue+ "\n"; } console.log(txt.split("\n")[0]); //prints the first point tag console.log(txt); // $(document).ready(function(){ //var x= $("point:nth-child(1)").text(); console.log(x); }); }) .catch(console.error);

...

about 4 years ago · Juan Pablo Isaza
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0

parseFromString devuelve una instancia de Documento donde puede usar las funciones proporcionadas para obtener todos los niños de varias maneras.

Aquí hay un POC:

 const data = "<root><object><coordinate>pixel</coordinate><type>rectangle</type><description>None</description><possibleresult><name>Intersection</name></possibleresult><points><point>684.999939,182.999985</point><point>682.568420,217.040604</point><point>612.568420,212.040604</point><point>614.999939,177.999985</point><point>684.999939,182.999985</point></points></object><object><coordinate>pixel</coordinate><type>rectangle</type><description>None</description><possibleresult><name>Small Car</name></possibleresult><points><point>1.000008,267.000000</point><point>-8.266037,257.072083</point><point>-0.000004,249.357117</point><point>9.266041,259.285034</point><point>1.000008,267.000000</point></points></object><object><coordinate>pixel</coordinate><type>rectangle</type><description>None</description><possibleresult><name>Small Car</name></possibleresult><points><point>267.000000,228.000000</point><point>244.000000,232.000000</point><point>241.944946,220.183472</point><point>264.944946,216.183472</point><point>267.000000,228.000000</point></points></object><object><coordinate>pixel</coordinate><type>rectangle</type><description>None</description><possibleresult><name>Small Car</name></possibleresult><points><point>480.591736,217.018555</point><point>458.591736,218.018555</point><point>458.000000,205.000000</point><point>480.000000,204.000000</point><point>480.591736,217.018555</point></points></object></root>"; const parser = new DOMParser(); const xml = parser.parseFromString(data, 'application/xml'); for(let objectTag of xml.querySelectorAll('root>object')) { console.log(`=== name: ${objectTag.querySelector('name').textContent} ===`) for(let x of objectTag.getElementsByTagName('point')) { console.log(x.textContent) } }

about 4 years ago · Juan Pablo Isaza Report
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