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How to check if an object key is in another object of objects

I have the following objects:

const allMembers = {
    "-Lz8YxHiwp8QZW3TqAFn": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHiwp8QZW3TqAFn"
    },
    "-Lz8YxHqQXWoaGOFRLrO": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHqQXWoaGOFRLrO"
    },
    "-Lz8YxHsMItaaTVNyQRE": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHsMItaaTVNyQRE"
    },
    "-Lz8YxHwuVBMWl0Go6C5": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHwuVBMWl0Go6C5"
    },
    "-Lz8YxHy0S-QkDaE1PkX": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHy0S-QkDaE1PkX"
    },
}

const attendanceData = {
    "-Lz8YxHiwp8QZW3TqAFn": true,
    "-Lz8YxHqQXWoaGOFRLrO": true,
    "-Lz8YxHsMItaaTVNyQRE": true,
    "-Lz8YxHwuVBMWl0Go6C5": false,
    "-Lz8YxHy0S-QkDaE1PkX": true,
    "-Lz8YxIFA1XGVmaNfNr3": false,
    "-Lz8YxIJVZnIIj7RgEzg": false,
}

I need to clean up the allMembers to only return if it's found as true in attendanceData. Here is my attempt but it's obviously not working. Also the way I'm doing it has to loop the first one over the other times.

const membersHere = Object.keys(allMembers).filter(memEl => Object.keys(attendanceData).find(attendEl => memEl == attendEl));
about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

  • Convert the allMembers object into an array of key value pairs using Object.entries.

  • Filter the items that have value true using Array.prototype.filter.

  • Transform the array back to an object using Object.fromEntries.

const 
  allMembers = {'-Lz8YxHiwp8QZW3TqAFn': {first: 'foo',last: 'bar',uid: '-Lz8YxHiwp8QZW3TqAFn'},'-Lz8YxHqQXWoaGOFRLrO': {first: 'foo',last: 'bar',uid: '-Lz8YxHqQXWoaGOFRLrO'},'-Lz8YxHsMItaaTVNyQRE': {first: 'foo',last: 'bar',uid: '-Lz8YxHsMItaaTVNyQRE'},'-Lz8YxHwuVBMWl0Go6C5': {first: 'foo',last: 'bar',uid: '-Lz8YxHwuVBMWl0Go6C5'},'-Lz8YxHy0S-QkDaE1PkX': {first: 'foo',last: 'bar',uid: '-Lz8YxHy0S-QkDaE1PkX'}},
  attendanceData = {'-Lz8YxHiwp8QZW3TqAFn': true,'-Lz8YxHqQXWoaGOFRLrO': true,'-Lz8YxHsMItaaTVNyQRE': true,'-Lz8YxHwuVBMWl0Go6C5': false,'-Lz8YxHy0S-QkDaE1PkX': true,'-Lz8YxIFA1XGVmaNfNr3': false,'-Lz8YxIJVZnIIj7RgEzg': false},
  filteredMembers = Object.fromEntries(
    Object.entries(allMembers).filter(([k]) => attendanceData[k])
  );

console.log(filteredMembers);

You can also do it using Array.prototype.reduce

const 
  allMembers = {'-Lz8YxHiwp8QZW3TqAFn': {first: 'foo',last: 'bar',uid: '-Lz8YxHiwp8QZW3TqAFn'},'-Lz8YxHqQXWoaGOFRLrO': {first: 'foo',last: 'bar',uid: '-Lz8YxHqQXWoaGOFRLrO'},'-Lz8YxHsMItaaTVNyQRE': {first: 'foo',last: 'bar',uid: '-Lz8YxHsMItaaTVNyQRE'},'-Lz8YxHwuVBMWl0Go6C5': {first: 'foo',last: 'bar',uid: '-Lz8YxHwuVBMWl0Go6C5'},'-Lz8YxHy0S-QkDaE1PkX': {first: 'foo',last: 'bar',uid: '-Lz8YxHy0S-QkDaE1PkX'}},
  attendanceData = {'-Lz8YxHiwp8QZW3TqAFn': true,'-Lz8YxHqQXWoaGOFRLrO': true,'-Lz8YxHsMItaaTVNyQRE': true,'-Lz8YxHwuVBMWl0Go6C5': false,'-Lz8YxHy0S-QkDaE1PkX': true,'-Lz8YxIFA1XGVmaNfNr3': false,'-Lz8YxIJVZnIIj7RgEzg': false},
  filteredMembers = Object.entries(allMembers).reduce(
    (r, [k, v]) => (attendanceData[k] && (r[k] = v), r),
    {}
  );

console.log(filteredMembers);

Other relevant documentations:

  • Comma operator (,)
about 4 years ago · Juan Pablo Isaza Report

0

You can use reduce method:

const allMembers = {
    "-Lz8YxHiwp8QZW3TqAFn": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHiwp8QZW3TqAFn"
    },
    "-Lz8YxHqQXWoaGOFRLrO": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHqQXWoaGOFRLrO"
    },
    "-Lz8YxHsMItaaTVNyQRE": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHsMItaaTVNyQRE"
    },
    "-Lz8YxHwuVBMWl0Go6C5": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHwuVBMWl0Go6C5"
    },
    "-Lz8YxHy0S-QkDaE1PkX": {
        "first": "foo",
        "last": "bar",
        "uid": "-Lz8YxHy0S-QkDaE1PkX"
    },
}

const attendanceData = {
    "-Lz8YxHiwp8QZW3TqAFn": true,
    "-Lz8YxHqQXWoaGOFRLrO": true,
    "-Lz8YxHsMItaaTVNyQRE": true,
    "-Lz8YxHwuVBMWl0Go6C5": false,
    "-Lz8YxHy0S-QkDaE1PkX": true,
    "-Lz8YxIFA1XGVmaNfNr3": false,
    "-Lz8YxIJVZnIIj7RgEzg": false,
}

const reduced = Object.entries(allMembers).reduce((data, [key, value]) => {
  if (attendanceData[key] ?? false)
    data[key] = value;
  return data;  
}, {});

console.log(reduced);

about 4 years ago · Juan Pablo Isaza Report

0

You can combine Object.keys(), Array.prototype.filter() and Array.prototype.reduce()

Code:

const allMembers = {'-Lz8YxHiwp8QZW3TqAFn': {first: 'foo',last: 'bar',uid: '-Lz8YxHiwp8QZW3TqAFn',},'-Lz8YxHqQXWoaGOFRLrO': {first: 'foo',last: 'bar',uid: '-Lz8YxHqQXWoaGOFRLrO',},'-Lz8YxHsMItaaTVNyQRE': {first: 'foo',last: 'bar',uid: '-Lz8YxHsMItaaTVNyQRE',},'-Lz8YxHwuVBMWl0Go6C5': {first: 'foo',last: 'bar',uid: '-Lz8YxHwuVBMWl0Go6C5',},'-Lz8YxHy0S-QkDaE1PkX': {first: 'foo',last: 'bar',uid: '-Lz8YxHy0S-QkDaE1PkX',},}

const attendanceData = {'-Lz8YxHiwp8QZW3TqAFn': true,'-Lz8YxHqQXWoaGOFRLrO': true,'-Lz8YxHsMItaaTVNyQRE': true,'-Lz8YxHwuVBMWl0Go6C5': false,'-Lz8YxHy0S-QkDaE1PkX': true,'-Lz8YxIFA1XGVmaNfNr3': false,'-Lz8YxIJVZnIIj7RgEzg': false,}
  
const result = Object
  .keys(allMembers)
  .filter((k) => attendanceData[k])
  .reduce((a, k) => (a[k] = allMembers[k], a), {})

console.log(result)

about 4 years ago · Juan Pablo Isaza Report
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