Im using react: 17.0.2 and react-router-dom: 6.3.0.
My current App.js snippet looks like this:
class App extends React.Component {
render() {
return (
<div className="App">
<Routes>
<Route element={<Layout/>}>
<Route path="/home" element={<Home/>} />
<Route path="/login" element={<Login/>} />
<Route path="/signup" element={<Signup/>} />
</Route>
<Route exact path='/' element={<Intro/>}/>
</Routes>
</div>
);
}
}
The route to '/' should not use the Layout component, so I need to exclude it from the context.
Within Layout.js I need to access the children like so:
const Layout = ({ children }) => {
console.log(children)
return (
<div>
<main>{children}</main>
</div>
);
};
But children are undefined in the above example. I can access children in Layout.js when I rewrite App.js to the below snippet, but then '/' is also rendered with the Layout.
class App extends React.Component {
render() {
return (
<div className="App">
<Layout>
<Routes>
<Route path="/home" element={<Home/>} />
<Route path="/login" element={<Login/>} />
<Route path="/signup" element={<Signup/>} />
<Route exact path='/' element={<Intro/>}/>
</Routes>
</Layout>
</div>
);
}
}
export default App;
How can I access children in Layout.js and render path '/' without the layout.
Route and Routes work a little differently in v6. The Route and React.Fragment components are the only valid children of the Routes component, and other Route components the only valid children of the Route. Layout routes must render an Outlet component for the nested routes to render their contents into.
import { Outlet } from 'react-router-dom';
const Layout = () => {
return (
<div>
<main>
<Outlet />
</main>
</div>
);
};