const cars = [
{
brand: "Chevrolet",
model: "Camaro",
dates: (3) ['2022/05/28', '2022/06/02', '2022/06/05']
},
{
brand: "Chevrolet",
model: "Camaro",
dates: (3) ['2022/05/30', '2022/06/02', '2022/06/05']
},
{
brand: "Chevrolet",
model: "Camaro",
dates: (3) ['2022/05/28', '2022/06/01', '2022/06/05']
}
]
I want to filter my object array based on another array
const arr2 = ["2022/06/02", "2022/06/05"];
I want to get results like that;
[
{
brand: "Chevrolet",
model: "Camaro",
dates: (3) ['2022/05/28', '2022/06/02', '2022/06/05']
},
{
brand: "Chevrolet",
model: "Camaro",
dates: (3) ['2022/05/30', '2022/06/02', '2022/06/05']
}
]
I used includes
let filtered = cars.filter((item) => item.dates.includes(arr2))
I got empty array.
when I pass a string to in includes I got filtered array.
let filtered = cars.filter((item) => item.dates.includes("2022/06/02"))
No I need to compare arr2. Its' length could be changed.
How can I pass an array to cars.include() function
[{}, {}].includes({})
returns false because it compares objects by object reference, not values in the object, so it's equivalent to
const a = {}; // new, empty object
const b = {}; // a different new, empty object
const c = {}; // yet another new, empty object
const answer = [a, b].includes(c) // false
Also, arrays are objects!
So that's why, when you pass an object (whether or not it's an array) into Array.prototype.includes, it returns false unless that same object is an element of the array.
You probably want something like this:
// Function that returns true if two arrays intersect
const includesAny = (arr1, arr2) => arr1.some(e1 => arr2.includes(e1));
const filterCarsByDates = (
datesSought => cars.filter(
car => includesAny(
cars.dates,
datesSought
)
)
);
let cars = [
{
brand: "Chevrolet",
model: "Camaro",
dates: ['2022/05/28', '2022/06/02', '2022/06/05']
},
{
brand: "Chevrolet",
model: "Camaro",
dates: ['2022/05/30', '2022/06/02', '2022/06/05']
},
{
brand: "Chevrolet",
model: "Camaro",
dates: ['2022/05/28', '2022/06/01', '2022/06/05']
}
];
let arr2 = ["2022/06/02", "2022/06/05"];
// A method that checks if `src` array contains all elements of `target` array
let checker = (src, target) => target.every(v => src.includes(v));
let filtered = cars.filter((item) => checker(item.dates, arr2));
console.log(filtered);You can use Array Filter with Set, Searching in Set is faster than Array.
const cars = [
{
brand: "Chevrolet",
model: "Camaro",
dates: ["2022/05/28", "2022/06/02", "2022/06/05"],
},
{
brand: "Chevrolet",
model: "Camaro",
dates: ["2022/05/30", "2022/06/02", "2022/06/05"],
},
{
brand: "Chevrolet",
model: "Camaro",
dates: ["2022/05/28", "2022/06/01", "2022/06/05"],
},
];
const arr2 = ["2022/06/02", "2022/06/05"];
const result = cars.filter((car) => {
const set = new Set(car.dates);
return arr2.every((date) => set.has(date));
});
console.log(result);