In mongodb you get data from the db like this:

const allUsers = await User.find() // returns an array of users

You can attach a sort method to the find() to sort the data depending on the specified field, 1 for ascending, -1 for descending, like this:

const allSortedUsers = await User.find().sort({ rank: 1 }) // returns an array of users sorted by rank

I am trying to understand how this works, and simulate it by my own But I couldn't so far figure out how they managed to attach a custom sort() method to another method that returns an array, or at least how they managed to overwrite the original built-in array sort() method so that it accepts an object argument that specifies the property we will use to sort

I tried to simulate the find() method, so I made it return a class with a custom sort() ... but the problem is that now my find() doesn't return an array of data, but an object, so I will have to dig deeper to get the actual array of data.. what I tried:

function find() {
  const data = // finding logic
  return new DataClass(data)
}

class DataClass {
  constructor(data) {
    this.data = data
  }

  sort(sortByObject) {
    const sortedData = // sorting logic
    return sortedData
  }
}

const users = await find().data // returns the data
const sortedUsers = await find().sort({rank:1}) // returns the sorted data

I want to be able to access the data through find() and not find().data

I also tried another approach, by attaching a custom sort method to the data array in the find() .. like this:

function find() {
  const data = // finding logic

  // attaching a sort() function to the data array
  data.sort = function(sortByObject) {
    // sorting logic
  }
  return data
}

but this also caused the returned array of data to have something like an extra item that could be iterated over.. which I don't want either .-.

Basically.. I want to simulate mongodb's find().sort({prop:1})