const dataArray = [
{ keyA: ["valueA1", "valueA2"] },
{ keyB: ["valueB1", "valueB2"] },
{ keyC: ["valueC1", "valueC2"] },
]
Put all obj's keys together as each new element and match inner array's elements with their respective index order.
The inner array's values are always fetched in the same index's order.
the following intended result explains better what I mean:
[
{
keyA: "valueA1",
keyB: "valueB1",
keyC: "valueC1",
},
{
keyA: "valueA2",
keyB: "valueB2",
keyC: "valueC2",
}
]
You can do something like this
const dataArray = [{
keyA: ['valueA1', 'valueA2']
},
{
keyB: ['valueB1', 'valueB2']
},
{
keyC: ['valueC1', 'valueC2']
},
];
const keys = dataArray.map((data) => Object.keys(data)[0]);
const result = [];
let keyIndex = 0;
let valueIndex = 0;
while (valueIndex < dataArray[0].keyA.length) {
const obj = {};
for (keyIndex = 0; keyIndex < keys.length; keyIndex++) {
obj[keys[keyIndex]] = dataArray[keyIndex][keys[keyIndex]][valueIndex];
}
result.push(obj);
valueIndex++;
}
console.log(result);