I want to set a function to the result of a ternary operator (that is returning one of two functions) and then call the result. My code looks like this:
const bar = (x: number) => {
// do something
}
const foo = (x: number) => {
// do something else
}
const my_function = condition ? bar : foo;
my_function(x)but I get a type error that my_function is not a function. Why doesn't this work, and how can I make it work? I have to call this function many times which is why I want to do it like this and not just call conditionally.
@m-s7's answer works. However, it's kind of messy.
IMHO better to commit something like this to production instead:
const bar = (x: number) => {
// do something
}
const foo = (x: number) => {
// do something else
}
const my_function = (x: number) => condition ? bar(x) : foo(x)
Here, you are creating a function in which you pass in the arg and return the result from the correct function based on the condition. It's pretty clean and easy to understand at a glance.