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pasar valor a genérico para obtener el tipo mecanografiado

tengo una funcion

 function getExtendedObject<T extends object>( currentObject: T ) { return { ...currentObject, newProp: "value1", anotherProp: () => "something" } }

necesito obtener el tipo de retorno de esta función para una entrada específica.

 type example = ReturnType<typeof getExtendedObject>

lo anterior me dará

 type example = object & { newProp: string; anotherProp: number; }

pero en lugar de objeto, quiero un valor específico. algo como,

 type example = { name: "john", marks: 91 } & { newProp: string; anotherProp: number; }

Cómo puedo conseguir esto

about 4 years ago · Juan Pablo Isaza
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