I'm trying to create this script: https://www.freecodecamp.org/learn/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/seek-and-destroy
After the comment "Verify and delete" is where I have the problem. I try to check all the elements form the array 'theCheck' with the elements from 'destroyers' and if the elements dont match then the script will push that value to the output array.
But it pushes every element regardless.
Expected output value: [1,1]
Current output value value: [1,2,3,1,2,3]
function destroyer(arr) {
let theCheck = [];
let destroyers = [];
let output = [];
for (let i = 1; i < arguments.length; i++) {
destroyers.push(arguments[i]);
}
for (let i = 0; i < arguments[0].length; i++) {
theCheck.push(arguments[0][i])
}
//Verify and delete
var j = 0
for (let i = 0; i < theCheck.length; i++) {
for (j = 0; j < destroyers.length; j++) {
if (theCheck[i] !== destroyers[j]) {
output.push(theCheck[i])
break;
}
}
}
console.log(theCheck)
console.log(destroyers)
console.log(output)
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);With the current code you're looping through the destroyers and anytime you find a destroyer that doesn't match the item you're checking you're adding it to the output. But because you've got two items in the destroyers array it is guaranteed that one of the two is not going to match the particular item that you're checking.
Below is a version where we work out whether any of the destroyers are found to match the item that we're checking, and only if it doesn't we're adding it to the output:
function destroyer(arr) {
let theCheck = [];
let destroyers = [];
let output = [];
for (let i = 1; i < arguments.length; i++) {
destroyers.push(arguments[i]);
}
for (let i = 0; i < arguments[0].length; i++) {
theCheck.push(arguments[0][i])
}
//Verify and delete
var j = 0
for (let i = 0; i < theCheck.length; i++) {
let found = false;
for (j = 0; j < destroyers.length; j++) {
if (theCheck[i] === destroyers[j]) {
found = true;
}
}
if(!found) output.push(theCheck[i]);
}
console.log(theCheck)
console.log(destroyers)
console.log(output)
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);You could use the includes function to tidy this up a little:
function destroyer(arr) {
let theCheck = [];
let destroyers = [];
let output = [];
for (let i = 1; i < arguments.length; i++) {
destroyers.push(arguments[i]);
}
for (let i = 0; i < arguments[0].length; i++) {
theCheck.push(arguments[0][i])
}
//Verify and delete
var j = 0
for (let i = 0; i < theCheck.length; i++) {
if(!destroyers.includes(theCheck[i]))
output.push(theCheck[i]);
}
console.log(theCheck)
console.log(destroyers)
console.log(output)
return arr;
}
destroyer([1, 2, 3, 1, 2, 3], 2, 3);function destroyer(input, ...arr) {
return input.filter(element => !arr.includes(element));
}
console.log(destroyer([1, 2, 3, 1, 2, 3], 2, 3));