I have this situation, I have an array and I need to filter it and get the indexes of the filtered items, like this example:
var arr = ['2022-05', '2023-01', '2022-04', '2022-02', '2023-08'];
I'm using this filter:
var filter = arr.filter(e => e.split("-")[0] == '2022'); //To get the values from 2022
And I get this result:
filter = ['2022-05', '2022-04', '2022-02'];
What I need to do now is to get also the index of these items, so it would be this:
filter = ['2022-05', '2022-04', '2022-02'];
index = [0,2,3]
How can I do that? Thanks.
Before filtering the array you can map it to a new array of objects that include the indexes.
var arr = ['2022-05', '2023-01', '2022-04', '2022-02', '2023-08'];
var output = arr.map((value, index) => ({index, value}))
.filter(e => e.value.split("-")[0] == '2022');
console.log(output);when matched, just add the desired index to the array
var arr = ['2022-05', '2023-01', '2022-04', '2022-02', '2023-08'];
var index = [];
var filter = arr.filter((e, indx) => {
const flag = e.split("-")[0] == '2022';
if (flag) {
index.push(indx)
}
return flag;
});
console.log(filter)
console.log(index)You could use the indexOf method:
filter.map(el => arr.indexOf(el));