Is it possible to use the find() method within an array of depth x?
For example, suppose I have the following array of objects, call it test:
[
{
"id": "1",
"title": "First",
},
{
"id": "2",
"title": "Second",
"movies": [
{
"id": "3",
"title": "Happy Gilmore",
"Actors": [
{
"id": "4",
"title": "John Doe",
},
{
"id": "5",
"title": "Jane Doe",
},
],
"Producers": [
{
"id": "6",
"title": "Max Smith",
},
{
"id": "7",
"title": "Richard Rocky",
},
],
},
{
"id": "10",
"title": "Billy Madison",
"Actors": [
{
"id": "40",
"title": "John Smith",
},
{
"id": "50",
"title": "Alex Doe",
},
],
"Producers": [
{
"id": "60",
"title": "Bob Smith",
},
{
"id": "70",
"title": "Polly Rocky",
},
],
}
]
}
]
Suppose I am looking for the "2" id. I can use the find() method to search the first level of the array and return the desired object by doing test.find(element => element.id === "2").
However, suppose I am now looking for the occurrence where the id is 4. As you can see from the above JSON, that element is within a sub array within test. Is there a way therefore where I can still search through test to find the element where id=4?
find cannot do this, but you can use it in a recursive approach:
function findDeep(arr, predicate) {
let res = arr.find(predicate);
if (res !== undefined) return res;
for (let obj of arr) {
for (let value of Object.values(Object(obj)).filter(Array.isArray)) {
res = findDeep(value, predicate);
if (res !== undefined) return res;
}
}
}
let test = [{"id": "1","title": "First",},{"id": "2","title": "Second","movies": [{"id": "3","title": "Happy Gilmore","Actors": [{"id": "4","title": "John Doe",},{"id": "5","title": "Jane Doe",},],"Producers": [{"id": "6","title": "Max Smith",},{"id": "7","title": "Richard Rocky",},],},{"id": "10","title": "Billy Madison","Actors": [{"id": "40","title": "John Smith",},{"id": "50","title": "Alex Doe",},],"Producers": [{"id": "60","title": "Bob Smith",},{"id": "70","title": "Polly Rocky",},],}]}];
let res = findDeep(test, obj => obj.id == "4");
console.log(res);