const ob = {
a: 1,
b: {
c: 3,
d: 6,
e: {
f: {
g: 3,
h: {
i: 5,
j: {
k: 7
}
}
}
}
}
};
Any methods to solve this code?
I have no idea how to solve this code.
For abovementioned input I would expect a result of 1 + 3 + 6 + 3 + 5 + 7 = 25. So what I want to return from a function sumObject(ob) is: 25
You can try reduce with recursion
The condition for the sum is
resultsumObject recursively with current resultconst ob = {
a: 1,
b: {
c: 3,
d: 6,
e: {
f: {
g: 3,
h: {
i: 5,
j: {
k: 7
}
}
}
}
}
};
function sumObject(data, result = 0) {
return Object.values(data).reduce((sum, value) => typeof value === 'number' ? sum + value : sumObject(value, sum), result)
}
console.log(sumObject(ob))If you don't understand some of the other answers, this is an easier solution to understand:
function sumObject(obj){
let result = 0;
for(let i of Object.values(obj)){ //we iterate through all values in obj
if(typeof i == "number"){ //if the current value of i is a number
result+=i; //then add that to the result
} else { //otherwise, it will be an object
result+=sumObject(i); //so we call the function on itself to iterate over this new object
}
}
return result; //finally, we return the total
}
console.log(sumObject(ob));
const ob = {
a: 1,
b: {
c: 3,
d: 6,
e: {
f: {
g: 3,
h: {
i: 5,
j: {
k: 7
}
}
}
}
}
};
const sum = data =>
Object
.keys(data)
.reduce((a,b) => a + (typeof(s = data[b]) == "number" ? s : sum(s)), 0);
console.log(sum(ob))