I have contacts that have SMS messages associated with them. Each sms record has properties such as time. Time is an timestamp string formatted as this example
2022-04-29T16:10:43-06:00
I am trying to sort this array of sms messages so that the latest one is the last one and the earliest one is the first one in the array. I thought I had it nailed down but apparently I don't. Its still not perfectly sorting at all.
this.getRecent()
.then(contacts => {
const sorted = contacts.map(contact => {
contact.sms = contact.sms.sort((a,b) => (a.time.localeCompare(b.time));
return contact;
});
// rest of code here
})
.catch(err => this.handleError(err));
Based on your question, I'm making the assumption that the contact.sms object contains an array of objects where time is a string (localeCompare is called). Since dates can have operators applied to them, you can sort them like any number.
const dates = [
new Date("2022-04-29T16:10:43-06:00"),
new Date("2023-04-29T16:10:43-06:00"),
new Date("2022-01-29T16:10:43-06:00")
]
console.log(dates)
dates.sort((a, b) => a - b)
console.log(dates)In your case,
// Sorts dates where the least recent is first.
contact.sms = contact.sms.sort((a,b) => new Date(a.time) - new Date(b.time));
You can parse them to a Date and compare the milliseconds:
contact.sms.sort((a,b) => new Date(a.time) - new Date(b.time));
Or swap a and b if you want to reverse the order.