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ViewsSort a string in Javascript
I have a string like the following. The string contains words which contain a number from 0 to 9 in them The number is the position they must have in the resulting string. If the string is empty, the result will be an empty string
Example: "en5 4terremoto NAS1A regi2stró L0a M6arte u3n"
Resultado:
"L0a NAS1A regi2stró u3n 4terremoto en5 M6arte"
how to go through the chain and order it, taking into account the number of each word?
Until now, I applied the split method to the original chain to separate them.
const mensaje = 'en5 4terremoto NAS1A regi2stró L0a M6arte u3n';
const arr = mensaje.split(' ');
console.log(arr);
I appreciate your help
·
Juan Pablo Isaza
1 answers
Answer question0
You could take each word, and remove all non-digits from it (with a regular expression), and use that as index in a result array:
const mensaje = "en5 4terremoto NAS1A regi2stró L0a M6arte u3n";
const result = [];
for (const word of mensaje.split(" ")) {
result[word.replace(/\D/g, "")] = word;
}
console.log(result);
·
Juan Pablo Isaza
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