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swapping array elements without a temporary variable

The following code:

var words = ['javascript', 'hmtl', 'css', 'python'];
            
words[0] = words[3];
words[3] = words[0];
        
alert(words);

...gives the below:

python,hmtl,css,python
  1. Why receive I python,hmtl,css,python, instead of python,hmtl,css,javascript, if there is no temporary variable?

Would you Guys be able to help with the above, please?

about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

if you want to swap without a temp variable use the ES6 array destruction syntax; simply do the following [words[0],words[3]]=[words[3],words[0]]

about 4 years ago · Juan Pablo Isaza Report
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