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Descartar error cuando la variable no está definida javascript

Cuando ejecuto este código

 return ( val.ticket.ticketNumber.toLowerCase().includes(inputText) || val.ticket.source.toLowerCase().includes(inputText) || val.ticket.lagoonMaterial.toLowerCase().includes(inputText) || val.ticket.vendor.toLowerCase().includes(inputText) || val.ticket.gallons.toLowerCase().includes(inputText); );

A veces falta una de las propiedades y eso me da este error

TypeError: undefined no es un objeto (evaluando 'val.ticket.vendor.toLowerCase')

¿Cómo puedo descartar esta propiedad sin tener que usar la declaración if?

about 4 years ago · Juan Pablo Isaza
1 answers
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Utilice operadores coalescentes nulos . Es como un OR ( || ), pero solo funciona para valores null e undefined . La colocación de ?? es como ||

 function getValue(num) { return num ?? 'Pass a number'; } console.log(getValue(5)); console.log(getValue());

about 4 years ago · Juan Pablo Isaza Report
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