Intento mostrar valueToday[1] para mi segundo elemento 'block-value' e intento mostrar valueToday[0] para mi primer elemento 'block-value'. Pero divs[i].querySelector(class).style.display = "" no funciona Mi filtro llamado para cada elemento:
let values = document.querySelectorAll('.value-h6'); let valueToday = document.querySelectorAll('.value-today'); let valueMonth = document.querySelectorAll('.value-month'); let valueYear = document.querySelectorAll('.value-year'); let divs = document.querySelectorAll('block-value'); function init() { // Clear data for (let i = 0; i < values.length; i++) { values[i].style.display = "none"; } for (let i = 0; i < valueToday.length; i++) { valueToday[i].style.display = 'block'; } } // user is coming, the default value is the dailyValue init(); function today() { init(); } function month() { for (let i = 0; i < values.length; i++) { values[i].style.display = "none"; } for (let i = 0; i < valueMonth.length; i++) { valueMonth[i].style.display = 'block'; } } function year() { for (let i = 0; i < values.length; i++) { values[i].style.display = "none"; } for (let i = 0; i < valueYear.length; i++) { valueYear[i].style.display = 'block'; } } <div class="ps-3 block-value" id="0"> <h6 class="value-h6 value-today">23%</h6> <h6 class="value-h6 value-month">24%</h6> <h6 class="value-h6 value-year">25%</h6> </div> <div class="ps-3 block-value" id="1"> <h6 class="value-h6 value-today">300</h6> <h6 class="value-h6 value-month">34</h6> <h6 class="value-h6 value-year">23</h6> </div> <li><button class="dropdown-item filter-btn filter-auj" onclick="today()">Aujourd'hui</button></li> <li><button class="dropdown-item filter-btn filter-mois" onclick="month()">Ce mois</button></li> <li><button class="dropdown-item filter-btn filter-annee" onclick="year()">Cette année</button></li>Pruebe display = 'none' ( https://www.w3schools.com/jsref/prop_style_display.asp#:~:text=The%20display%20property%20also%20allows,its%20original%20position%20and%20size. ) W3schools tiene excelente documentación para estas cosas ;-)