I need to perform filter in the array of objects to get all the keys. Although, whenever there is a obj inside of that key, I would need to get the key name and concat with the key name from the obj, so for example:
const data = [ id: 5, name: "Something", obj: { lower: True, higher: False } ]
result = ["id", "name", "obj.lower", "obj.higher"]
I could manage to do the above code, but, if there is more objs inside the data, I would need to keep adding a if condition inside of my logic, I would like to know if there is any other way, so it doesn't matter how many objects I have inside the objects, It will concat always.
The code I used from the above mention:
const itemsArray = [
{ id: 1, item: "Item 001", obj: { name: 'Nilton001', message: "Free001", obj2: { test: "test001" } } },
{ id: 2, item: "Item 002", obj: { name: 'Nilton002', message: "Free002", obj2: { test: "test002" } } },
{ id: 3, item: "Item 003", obj: { name: 'Nilton003', message: "Free003", obj2: { test: "test003" } } },
];
const csvData = [
Object.keys(itemsArray[0]),
...itemsArray.map(item => Object.values(item))
].map(e => e.join(",")).join("\n")
// Separating keys
let keys = []
const allKeys = Object.entries(itemsArray[0]);
for (const data of allKeys) {
if (typeof data[1] === "object") {
const gettingObjKeys = Object.keys(data[1]);
const concatingKeys = gettingObjKeys.map((key) => data[0] + "." + key);
keys.push(concatingKeys);
} else {
keys.push(data[0])
}
}
//Flating
const flattingKeys = keys.reduce((acc, val: any) => acc.concat(val), []);
What I would like to achieve, lets suppose I have this array of object:
const data =
[
{ id: 10, obj: {name: "Name1", obj2: {name2: "Name2", test: "Test"}}}
...
]
Final result = ["id", "obj.name", "obj.obj2.name2", "obj.obj2.test"]
OBS: The first obj contains all the keys I need, no need to loop through other to get KEYS.
I would like to achieve, all the keys from the first object of the array, and if there is objects inside of objects, I would like to concat the obj names (obj.obj2key1)
You could map the key or the keys of the nested objects.
const
getKeys = object => Object
.entries(object)
.flatMap(([k, v]) => v && typeof v === 'object'
? getKeys(v).map(s => `${k}.${s}`)
: k
),
getValues = object => Object
.entries(object)
.flatMap(([k, v]) => v && typeof v === 'object'
? getValues(v)
: v
),
data = { id: 1, item: "Item 001", obj: { name: 'Nilton001', message: "Free001", obj2: { test: "test001" } } },
keys = getKeys(data),
values = getValues(data);
console.log(keys);
console.log(values);.as-console-wrapper { max-height: 100% !important; top: 0; }something like this
const itemsArray = [
{ id: 1, item: "Item 001", obj: { name: 'Nilton001', message: "Free001", obj2: { test: "test001" } } },
{ id: 2, item: "Item 002", obj: { name: 'Nilton002', message: "Free002", obj2: { test: "test002" } } },
{ id: 3, item: "Item 003", obj: { name: 'Nilton003', message: "Free003", obj2: { test: "test003" } } },
];
const item = itemsArray[0];
const getAllKeys = (obj, prefix=[]) => {
if(typeof obj !== 'object'){
return prefix.join('.')
}
return Object.entries(obj).flatMap(([k, v]) => getAllKeys(v, [...prefix, k]))
}
console.log(getAllKeys(item))You can use recursion as follows. Since typeof([1,3,5]) is object, we also have to confirm that value is not an array, !Array.isArray(value):
const obj = { id: 10, obj: {name: "Name1", obj2: {name2: "Name2", test: "Test"}}};
const getKeys = (o,p) => Object.entries(o).flatMap(([key,value]) =>
typeof(value) === 'object' && !Array.isArray(value) ?
getKeys(value, (p?`${p}.`:"") + key) :
(p ? `${p}.`: "") + key
);
console.log( getKeys(obj) );