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ViewsHow to user filter with Firestore database in React Native?
I want to filter the firestore query to get all docs that do not contain a specific value.
I used @react-native-firebase
import firestore from '@react-native-firebase/firestore';
const getUnreadDocs = async () => {
const unreadDocs = await firestore()
.collection('rooms')
.doc('aDRKtxbhG9g5IfbKcsa4')
.collection('messages')
.where('seen', 'not-in', ['7B6jaZngXeN7V4r3eRoDBdlcj6m2'])
.get();
console.log(`unreadDocs`, unreadDocs);
};
docs return from the query
How data is stored?
we have collection
rooms Collection -> Docs -> fields
|
V
messages Collection -> Docs -> fields
What should the query return?
as we mention in query, docs should not contain 7B6jaZngXeN7V4r3eRoDBdlcj6m2 in the seen field
so, query should return only one doc i.e.
1 answers
Answer question0
The in/not-in operators checks if a current single-value field has a value that exists/does not exist in a list of values you specify. But your seen field is an array, which won't work with this operator.
Instead you'll want to use array-contains on that to check if a value is present. There is no equivalent array-does-not-contain operator to check whether a value is not present in the array field.
Also see: