File structure:
testAPI
contactDetail
dispMobNo.js
myModule.js
index.js
index.js
const express = require("express");
const app = express();
const port = process.env.port || 3000;
const getCustNo = require("./contactDetail/dispMobNo");
app.use(getCustNo);
app.listen(port, console.log("server running on port: " + port));
dispMobNo.js
const express = require("express");
const router = express.Router();
router.get("/", getContactNo);
function getContactNo(req, res)
{
console.log(req.query);
res.send(req.query);
}
module.exports = router;
Above code is working BUT I want to remove getContactNo function from this file and want to put it in a separate file. I mean, I don’t want to put any code inside/under API endpoint. I want to put getContactNo function in separate file and want to call from API endpointcallback function. So, how to do this?
Modified version of dispMobNo.js:
const express = require("express");
const router = express.Router();
router.get("/", getContactNo);
module.exports = router;
myModule.js
function getContactNo(req, res)
{
console.log(req.query);
res.send(req.query);
}
module.exports = getContactNo;
you can do this way
// controller.js file
export async getData = (req,res) => {
// your logic
}// route.js file
const Controller = require("./controller");
route.get('/api-endpoint',async(req,res)=>{
Controller.getData(req,res);
})EDIT for simpler explanation
// controller.js file
function getData(req,res){
//your logic
}
module.exports = {getData}
// main route file
const {getData} = require('./controller.js');
route.get('/api-endpoint',function(req,res){
getData(req,res);
});
You are almost there.
Modified version of dispMobNo.js:
const myModule = require('./my-module.js');
const express = require("express");
const router = express.Router();
router.get("/", myModule.getContactNo);
module.exports = router;
my-module.js
function getContactNo(req, res)
{
console.log(req.query);
res.send(req.query);
}
module.exports = {
getContactNo
};
Above, I have assumed that, both files are in same directory.