Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

99
Views
Filter array object by array of Boolean values dynamically

I have my array object in the following format

menuItem = [{
    "name": "MOZZARELLA DI BUFALA & TOMATOES",
    "gluten": true,
    "eggs": false,
    "dairy": true,
     ...
},...

I want to filter hundreds of menuItems by the allergen values (Boolean).

While the following code does the trick:

menuItem.filter(el => !el.gluten && !el.fish && !el.soy && !el.dairy)"

The allergens are hardcoded and repetitive. I am struggling to make the code dynamic and elegant.

I tried the following solution

menuItem.filter(el => !el[allergens])"
var allergens = ['gluten', 'fish', 'soy', 'dairy']

However, it only works correctly with one allergen value. Multiple values as in the above example do not filter anything.

about 4 years ago · Santiago Trujillo
2 answers
Answer question

0

First extract the name property, then check that the rest of the properties in the object are falsey.

menuItem.filter(
  ({ name, ...rest }) => Object.values(rest).every(val => !val)
);

Ideally, I'd prefer to restructure the input array so the allergies are in a separate property, perhaps:

menuItem = [{
    "name": "MOZZARELLA DI BUFALA & TOMATOES",
    allergens: {
        "gluten": true,
        "eggs": false,
        "dairy": true,

to make accessing them easier.

menuItem.filter(
  ({ allergens }) => Object.values(allergens).every(val => !val)
);
about 4 years ago · Santiago Trujillo Report

0

You could use .some or .every, whichever match your case

const allergens = ['gluten', 'fish', 'soy', 'dairy']

const res = menuItem.filter(
  (el) => !allergens.every((allergen) => el[allergen])
);
// equivalent to `menuItem.filter(el => !el.gluten && !el.fish && !el.soy && !el.dairy)`

const menuItem = [
  {
    name: 'dish A',
    gluten: true,
    fish: true,
    soy: true,
    dairy: true,
  },
  {
    name: 'dish B',
    gluten: true,
    fish: true,
    soy: false,
    dairy: true,
  },
];

const allergens = ['gluten', 'fish', 'soy', 'dairy'];

const res = menuItem.filter(
  (el) => !allergens.every((allergen) => el[allergen])
);

console.log(res);

about 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!