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Why not getting output with arrow function?

When i'm trying buildGraph function with normal function its working properly but with arrow function getting empty obj as output. Help needed.

var roads = [
    "Alice's House-Bob's House", "Alice's House-Cabin",
    "Alice's House-Post Office", "Bob's House-Town Hall",
    "Daria's House-Ernie's House", "Daria's House-Town Hall",
    "Ernie's House-Grete's House", "Grete's House-Farm",
    "Grete's House-Shop", "Marketplace-Farm",
    "Marketplace-Post Office", "Marketplace-Shop",
    "Marketplace-Town Hall", "Shop-Town Hall"
   ];

let buildGraph = (edges) => {
    let obj = {}
    let addEdge = (from, to) => (
        obj[from] === null ? obj[from] = [to] : obj[from]?.push(to)
    )
    edges.map(r => r.split("-")).map(([from, to]) => addEdge(from, to))
    return obj;
}
console.log(buildGraph(roads))   // Output: {}

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

Replace null with undefined. If a key is not found in an object it returns undefined not null.

var roads = [
  "Alice's House-Bob's House",
  "Alice's House-Cabin",
  "Alice's House-Post Office",
  "Bob's House-Town Hall",
  "Daria's House-Ernie's House",
  "Daria's House-Town Hall",
  "Ernie's House-Grete's House",
  "Grete's House-Farm",
  "Grete's House-Shop",
  "Marketplace-Farm",
  "Marketplace-Post Office",
  "Marketplace-Shop",
  "Marketplace-Town Hall",
  "Shop-Town Hall",
];

let buildGraph = (edges) => {
  let obj = {};
  let addEdge = (from, to) =>
    obj[from] === undefined ? (obj[from] = [to]) : obj[from]?.push(to);
  edges.map((r) => r.split("-")).map(([from, to]) => addEdge(from, to));
  return obj;
};

console.log(buildGraph(roads));

about 4 years ago · Juan Pablo Isaza Report

0

It's not the arrow function, it's this comparison:

obj[from] === null

The === operator performs an exact type-comparison, and for properties which don't exist on an object the exact type of the property is not null, it's undefined. So that comparison is false and the property is never added to the object.

Compare it to undefined instead:

var roads = [
    "Alice's House-Bob's House", "Alice's House-Cabin",
    "Alice's House-Post Office", "Bob's House-Town Hall",
    "Daria's House-Ernie's House", "Daria's House-Town Hall",
    "Ernie's House-Grete's House", "Grete's House-Farm",
    "Grete's House-Shop", "Marketplace-Farm",
    "Marketplace-Post Office", "Marketplace-Shop",
    "Marketplace-Town Hall", "Shop-Town Hall"
   ];

let buildGraph = (edges) => {
    let obj = {}
    let addEdge = (from, to) => (
        obj[from] === undefined ? obj[from] = [to] : obj[from]?.push(to)
    )
    edges.map(r => r.split("-")).map(([from, to]) => addEdge(from, to))
    return obj;
}
console.log(buildGraph(roads))   // Output: {}

about 4 years ago · Juan Pablo Isaza Report

0

You could also use .reduce(). Its often used if you want to group something together

var roads = [
    "Alice's House-Bob's House", "Alice's House-Cabin",
    "Alice's House-Post Office", "Bob's House-Town Hall",
    "Daria's House-Ernie's House", "Daria's House-Town Hall",
    "Ernie's House-Grete's House", "Grete's House-Farm",
    "Grete's House-Shop", "Marketplace-Farm",
    "Marketplace-Post Office", "Marketplace-Shop",
    "Marketplace-Town Hall", "Shop-Town Hall"
   ];

let result = roads.reduce((obj, road) => {
  let [from, to] = road.split("-")
  obj[from] ? obj[from].push(to) : obj[from] = [to]
  return obj
},{})

console.log(result)

about 4 years ago · Juan Pablo Isaza Report
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