Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

139
Views
for loop method for finding non-sequential slots (holes) in an array

Just as the title says - I'm trying to find the first empty (missing) number (hole) in an array using for-loop or, if the array is sequential and starting from 1 through 7 for example, I'll need the next integer after the last array item, in this case 8.

Need only one hole per whole iteration returning the found value.

My logic is ok when it comes to the first condition (array starting with a value higher than 1) but the from the next to conditions the last one is always picked up.

In a nutshell:

  • in an array of [2,3,4,5,6,7] I need "1" and I get it;
  • in an array of [1,2,3,4,6,7] I need "5" but I get "8".
  • in an array of [1,2,3,4,5,6,7] I need "8" and I get it.

const numbers = [1, 2, 3, 4, 6, 7];

document.getElementById("demo").innerHTML = numbers;
let hole;

holeFinder()

function holeFinder() {
  for (let i = 0; i < numbers.length; i++) {
    if (numbers[0] > 1) {
      /*  console.log(numbers[0]) */
      hole = 1;
      document.getElementById("demo").innerHTML += "<br>1: hole: " + hole;
      return hole;
    }

    if (numbers[i] > 1) {
      if ((numbers[i] - numbers[i - 1]) > 1) {
        hole = (numbers[i - 1] + 1)
        document.getElementById("demo").innerHTML += "<br>2: hole: " + hole;
        return hole;
      }

      if ((numbers[i] - numbers[i - 1]) == 1) {
        hole = numbers[numbers.length - 1] + 1;
        document.getElementById("demo").innerHTML += "<br>3: hole: " + hole;
        return hole;
      }
    }
  }
}
<h2>for loop method for finding non-sequential slots (holes) in an array</h2>
<p id="demo"></p>

JSFIDDLE

What's wrong with my logic?

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

You can do something like this

const arr1 = [1, 2, 3, 4, 6, 7]
const arr2 = [1, 2, 4, 5, 6, 7]
const arr3 = [1, 2, 3, 4, 5, 6, 7]


const findHole = arr => {
 for(let i = 0; i < arr.length; i++){
  if(arr[i] !== i + 1){
    return i + 1
  }
 }
 return arr.length + 1
}

console.log(findHole(arr1))
console.log(findHole(arr2))
console.log(findHole(arr3))

about 4 years ago · Juan Pablo Isaza Report

0

You could also use a while loop and find the missing number to break the loop.

const one = [2, 3, 4, 5, 6, 7];
const two = [1, 2, 3, 4, 6, 7];
const three = [1, 2, 3, 4, 5, 6, 7];

function findHole(numbers) {
  let count = 0;
  let hole = null;

  while (!hole) {
    count++
    const number = count;
    
    // if the array does not contain number, assign the number
    // as the missing hole number
    if (!numbers.includes(number)) {
      hole = number;
    }
  }

  return hole;
}

document.getElementById("demo").innerHTML += "1: hole: " + findHole(one) + '<br>';
document.getElementById("demo").innerHTML += "2: hole: " + findHole(two) + '<br>';
document.getElementById("demo").innerHTML += "3: hole: " + findHole(three) + '<br>';
<div id="demo"></div>

about 4 years ago · Juan Pablo Isaza Report

0

You enter the second part of the second if statement

if ((numbers[i] - numbers[i - 1]) == 1) {
    hole = numbers[numbers.length - 1] + 1;
    document.getElementById("demo").innerHTML += "<br>3: hole: " + hole;
    return hole;
}

on the second iteration of the loop, so as long as you don't find the hole at the first index, it will always return the last array element increased by one. You should check this condition only at the last element of your array.

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!