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Viewsfind specific word in a string function is acting... odd (javascript)
Alright, so I have this function that is suppose to log a specific word it finds in a string into the console. But it kinda... yeah it don't work.
function foo(input) {
for (var i = 0; i < input.length; i++) {
const character = input[i]
// To make sure it doesnt always get
// the very first blank space I do the following \/ (I think this is the trouble area)
const word = input.substring(i, input.substring(i, input.length).indexOf(' '))
console.log(word)
if (word == "foo bar") {
console.log(word)
console.log("worked!") // <- currently does not fire
// word should only print "foo bar" without linebreaks
}
}
}
foo(" foo bar ");I don't even know how to explain what is happening. But I am sure this scary image will give you an idea.
the expected output, with some line breaks above or below, is:
"f"
"fo"
"foo"
"foo "
"foo b"
"foo ba"
"foo bar"
"worked!"
ALSO keep it mind that this does not work with or without line breaks (I testing both) and I would like it to work with both.
examples:
// single line (does not work)
foo(" foo bar ")
// line breaks (does not work)
foo(`
foo bar
`)
·
Juan Pablo Isaza
1 answers
Answer question0
Define word out of the for loop... And add the current character to it at each iteration.
const input = "foo bar"
function foo(input) {
let word = "" // Define it out of the loop
for (var i = 0; i < input.length; i++) {
const character = input[i]
word += character // add the current loop character here
console.log(word)
if (word == "foo bar") {
console.log("worked!") // <- is firing now
}
}
}
foo(input)From comment:
if I have the string "This is a foo bar lalalalala" I want to get just the "foo bar" part.
Then using match would be the way.
const input = "This is a foo bar lalalalala"
function foo(input) {
let match = input.match(/foo bar/)
if (match) {
console.log("worked!") // <- is firing now
}
}
foo(input)
·
Juan Pablo Isaza
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