In JavaScript Try catch block how to retry the same . am facing once scenario any one ca give the best approach to handle this ?
for Example :
const getMyDetails = async()=>{
try{
await getName();
}catch(err){
//But Above FAIL due to some issue
// so I want to try the same again "getName" here until the success - 'not single time'
}
// Second Method for get data
const getName = async()=>{
try{
here am calling API or any kind of subscription But here its failing so am throwing error
}catch(err){
throw new Error(err);
}
getMyDetails()
Note: may be the fail reason like Databse events or some other subscriptions etc..
instead of calling the method name in catch .. what will be the best approach for retry
Thanks in advance
Just Calling Itself If It Fails Will Do The Job
const getMyDetails = async()=>{
try{
await getName();
}catch(err){
getMyDetails()
}
// Second Method for get data
const getName = async()=>{
try{
// Method
}catch(err){
throw new Error(err);
}
getMyDetails()
Here you can see an example behavior and the implementation logic of calling an async function N number of times, only until no errors are thrown.
// We must be inside of an async function to be able to call await
(async function() {
// Example async function which returns the value only if no errors are thrown,
// otherwise calls itself to retry the async call
async function getMyDetails() {
try {
return await getName();
} catch (error) {
return getMyDetails();
}
}
// Example async function which returns value only if the random number is even,
// otherwise throws an Error (simulating an API error response)
async function getName() {
return new Promise((resolve, reject) => {
let randomNumber = Math.floor(Math.random());
if (randomNumber % 2 === 0) {
resolve("Random Name");
}
reject("Example API Error has occured.")
});
}
let myDetails = await getMyDetails();
console.log(myDetails);
})();