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0

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JS merge two subarray using map

I use the following to merge two arrays:

var mySeries = [
    { name: '4', data: [4] },
    { name: '3', data: [3] }
];
var mySeries1 = [
    { name: '5', data: [0] },
    {name: '4', data:[0]},
    {name: '3', data:[0]},
    {name: '2', data:[0]},
    { name: '1', data: [0] }
];

var res = mySeries1.map(obj => mySeries.find(o => o.name === obj.name) || obj);
console.log(res);

Works great; however, my challenge is my array is structured as:

var myArray = [{ 
    mySeries : [
        { name: '4', data: [4] },
        { name: '3', data: [3] }],
    mySeries1 : [
        { name: '5', data: [0] },
        { name: '4', data: [0] },
        { name: '3', data: [0] },
        { name: '2', data: [0] },
        { name: '1', data: [0] }]
    }];
];

So I need to map subarrays, tried using the following:

var res = myArray.mySeries1.map(obj => myArray.mySeries.find(o => o.name === obj.name) || obj);

I get this error:

Cannot read properties of undefined (reading 'map')

How can I point to the subarray?

about 4 years ago · Santiago Trujillo
2 answers
Answer question

0

var myArray = [{ 
    mySeries : [
        { name: '4', data: [4] },
        { name: '3', data: [3] }],
        mySeries1 : [
            { name: '5', data: [0] },
            { name: '4', data: [0] },
            { name: '3', data: [0] },
            { name: '2', data: [0] },
            { name: '1', data: [0] }
        ]
        }];

var res = myArray[0].mySeries1.map(obj => myArray[0].mySeries.find(o => o.name === obj.name) || obj);
console.log(res)

about 4 years ago · Santiago Trujillo Report

0

you could change your array to dictionary and iterate it like you already did.

var myArray = { 
    mySeries : [
        { name: '4', data: [4] },
        { name: '3', data: [3] }],
    mySeries1 : [
        { name: '5', data: [0] },
        { name: '4', data: [0] },
        { name: '3', data: [0] },
        { name: '2', data: [0] },
        { name: '1', data: [0] }]
    };

i.e. var res = myArray.mySeries1.map(obj => myArray.mySeries.find(o => o.name === obj.name) || obj);

about 4 years ago · Santiago Trujillo Report
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