I have an async function and I need to do the following in this function:
This is what I did:
public async foo(): Promise<B> {
const promiseA: Promise<A> = ajaxRequest(...);
promiseA.then((a) => {
return new Promise<B>((resolve) => {
const b: B = process(a);
resolve(b);
})
});
promise.catch(e => {
console.error(e);
return new Promise<B>((resolve) => {
resolve(null);
})
})
}
And I get A function whose declared type is neither 'void' nor 'any' must return a value. compilation error. Could anyone say how to do it?
Your function seems to simplify to
class Something {
public async foo(): Promise<B | null> {
try {
const a = await ajaxRequest(...);
return process(a);
} catch (e) {
console.error(e);
return null;
}
}
}
assuming process returns B.