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Difundir el argumento de la función literal del objeto y devolver la abreviatura

¿Hay una forma más corta de escribir esto? (Difundir el argumento literal del objeto y devolver todas sus propiedades):

 export const selectUser = ({ fullName, email, userType }) => ({ fullName, email, userType, }), );
about 4 years ago · Santiago Trujillo
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Suponiendo (desde "devolver todas sus propiedades" ) que el objeto tiene exactamente estas 3 propiedades, puede:

 export const selectUser = obj => ({ ...obj });
about 4 years ago · Santiago Trujillo Report
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