hi everyone i am jonnathan i am trying to create a calculator in javascript and i am following a tutorial on youtube but for some reason if i add 1 and 1 together the result 2 is alerting
var number1 = prompt("Input the first number");
var op = prompt("Input operator")
var number2 = prompt("Input 3rd number")
if (op == "+") {
if (number1 == "1") {
if (number2 == "1") {
alert("2");
}
if (number2 == "2") {
alert("3");
}
if (number2 == "3") {
alert("4");
}
if (number2 == "4") {
alert("5");
}
if (number2 == "5") {
alert("6");
}
if (number2 == "6") {
alert("7");
}
if (number2 == "7") {
alert("8");
}
if (number2 == "8") {
alert("9");
}
if (number2 == "9") {
alert("10");
}
}
if (number2 == "1") {
if (number1 == "1") {
alert("2");
}
if (number1 == "2") {
alert("3");
}
if (number1 == "3") {
alert("4");
}
if (number1 == "4") {
alert("5");
}
if (number1 == "5") {
alert("6");
}
if (number1 == "6") {
alert("7");
}
if (number1 == "7") {
alert("8");
}
if (number1 == "8") {
alert("9");
}
if (number1 == "9") {
alert("10");
}
}
}twice there are no errors in the console either that i think could help me with this issue
so far the calculator only adds numbers and only does it through 1 ti 9. how can i fix this error?
In your code:
if (op == "+") {
if (number1 == "1")
{
if (number2 == "1")
{
alert("2");
}
This section is alerting "2" first. And then this section:
if (number2 == "1") {
if (number1 == "1") {
alert("2");
}
That's why it's appearing twice. You can write the program as:
let number1 = parseInt(prompt("Input the first number"));
let op = prompt("Input the operator");
let number2 = parseInt(prompt("Input the second number"));
if (op == '+')
alert(number1 + number2);
else if (op == '-')
alert(number1 - number2);
else if (op == '*')
alert(number1 * number2);
else if (op == '/')
alert(number1 / number2);
else
alert("Please enter a valid operator");
Here we used parseInt(), that returns the first integer from a string.