context: Two javascript classes in separate files, each integrating a different external service and being called in a express.js router.

See "problematic code" below:

• route

routes.post('/aws', upload.single('file'), async (req, res) => {
    const transcribeParams = JSON.parse(req.body.options)
    const bucket = 'bucket-name'

    const data = await ( await ( await awsTranscribe.Upload(req.file, bucket)).CreateJob(transcribeParams)).GetJob()

    res.send(data) 
})  

• S3 class

class AmazonS3 {
    constructor() {
        this.Upload = this.Upload
    }

    async Upload(file, bucket) {
        const uploadParams = {
            Bucket: bucket,
            Body: fs.createReadStream(file.path),
            Key: file.filename,
        }

        this.data = await s3.upload(uploadParams).promise()

        return this
    }
}  

• Transcribe class

class Transcribe extends AwsS3 {
    constructor() {
        super()
        this.CreateJob = this.CreateJob
        this.GetJob = this.GetJob
    }

    async CreateJob(params) {
        if(this.data?.Location) {
            params.Media = { ...params.Media, MediaFileUri: this.data.Location }
        }

        this.data = await transcribeService.startTranscriptionJob(params).promise()

        return this
    }

    async GetJob(jobName) {
        if(this.data?.TranscriptionJob?.TranscriptionJobName) {
            jobName = this.data.TranscriptionJob.TranscriptionJobName
        }

        this.data = await transcribeService.getTranscriptionJob({TranscriptionJobName: jobName}).promise()

        return this
    }
}

problem: the problem is with the chained awaits in the router file:
await ( await ( await awsTranscribe.Upload...
Yes, it does work, but it would be horrible for another person to maintain this code in the future.
How can i make so it would be just
awsTranscribe.Upload(req.file, bucket).CreateJob(transcribeParams).GetJob() without the .then?

PS: For those wondering why the last code is in quotes, it was accusing it of not properly formatted code.