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Pass value of input to other input without onclick

I have a working code to pass value from one id to another, but to do that I need a button to pass it onclick. I want to pass the value without a button directly to the other input. As I did my research i just saw onclick solutions.. Is there any other way or am I stuck with this option

My Code:

window.onload = function() {
    document.getElementById('button').onclick = function() {
        document.getElementById('email2').value = document.getElementById('email').value;
        document.getElementById('firma2').value = document.getElementById('firma').value;
        document.getElementById('name2').value = document.getElementById('name').value;
        document.getElementById('nummer2').value = document.getElementById('nummer').value;

    }
};
about 4 years ago · Juan Pablo Isaza
2 answers
Answer question

0

Try this solution:

const textInput = document.querySelector('#text');
const checkboxInputs = document.querySelectorAll('[id^=checkbox]');
const secondInput = document.querySelector('#second');
const thirdInput = document.querySelector('#third');

textInput.addEventListener('input', (e) => {
  secondInput.value = e.target.value;
})

textInput.addEventListener('change', (e) => {
  thirdInput.value = e.target.value;
})

const checkboxesSet = new Set();

checkboxInputs.forEach(checkboxInput =>
  checkboxInput.addEventListener('change', (e) => {
    const label = document.querySelector(`label[for=${e.target.id}]`).innerText;
    
    checkboxesSet[e.target.checked ? 'add' : 'delete'](label);
    
    const text = [...checkboxesSet].join(', ');

    secondInput.value = text;
    thirdInput.value = text;
  })
)
<label for="text">Text input</label>
<input id="text">
<br/>
<label for="checkbox1">Checkbox input 1</label>
<input id="checkbox1" type="checkbox">
<br/>
<label for="checkbox2">Checkbox input 2</label>
<input id="checkbox2" type="checkbox">
<br/>
<label for="second">While typing</label>
<input id="second">
<br/>
<label for="third">At the end</label>
<input id="third">

about 4 years ago · Juan Pablo Isaza Report

0

You could consider using onchange instead of onclick.

about 4 years ago · Juan Pablo Isaza Report
Answer question
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