title basically. The question says create a function that takes in a string and returns true when the string starts and ends with a vowel. I must have read every possibly helpful/similar thread on here and still stuck. Please help
Tried too many things to even list. Its been literally hours I've been bashing my head against this problem.
function test( word ){
word = word.toUpperCase();
let last = word[ word.length - 1 ];
let vowels = [ 'A', 'E', 'I', 'O', 'U' ]
if( vowels.includes( word[0]) && vowels.includes( last ) ){
return true
}else{
return false
}
}
:-)
You know how to create and execute a function?
You understand what startsWith and endsWith with does?
You know the && (and) and || (or) operators?
Try something like this:
function startsEndsWithAVowel(aString) {
return (aString.startsWith('a') || aString.startsWith('e') || aString.startsWith('i') || aString.startsWith('o') || aString.startsWith('u')) && (aString.endsWith('a') || aString.endsWith('e') || aString.endsWith('i') || aString.endsWith('o') || aString.endsWith('u'));
}
Add uppercase vowels too.
This solution uses only a few constructs. If You learn more JavaScript you come up much better solutions.