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Accessing variable outside a function in React JS Frontend

I have written this code to access my variable outside the function.The value of res outside the function is undefined. the outside console.log should print the url which is assigned to res inside the function. I will use this response in my anchor tag to open the url in res variable. What am I doing wrong?

const firebaseApp = initializeApp(firebaseconfig)
const storage = getStorage(firebaseApp)
var res;
  const downloadurl = function() { getDownloadURL(ref(storage, 'files/linpeas.txt'))
    .then((url) => {
       res = url
       console.log(res)
    })};
      
console.log(res)
about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

Try using the useState() to store res and the useEffect() to update res when this changes;

const firebaseApp = initializeApp(firebaseconfig)
const storage = getStorage(firebaseApp)
const [res, setRes] = useState();

const downloadurl = () => { getDownloadURL(ref(storage, 'files/linpeas.txt'))
    .then((url) => {
       setRes(url);
       console.log(res)
    })
    .catch((error) => console.log(error));
};
      
useEffect(() => {
    console.log(res);
  }, [res]);
about 4 years ago · Juan Pablo Isaza Report
Answer question
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