The following code is replacing opening and closing straight double quotes by opening and closing curly double quotes:
const string = `Not dialogue not dialogue.
"Dialogue dialogue.
"Dialogue dialogue."
"Dialogue," not dialogue. "Dialogue."`
const result = string.replace(/"([^"\n\r]*)"/g, '“$1”')
console.log(result)How to modify this code so the opening straight double quote in "Dialogue dialogue (second line) is also replaced by an opening curly double quote (without adding a closing curly double quote at the end of the line)?
Desired output:
Not dialogue not dialogue.
“Dialogue dialogue.
“Dialogue dialogue.”
“Dialogue,” not dialogue. “Dialogue.”
You can use
const string = `Not dialogue not dialogue.
"Dialogue dialogue.
"Dialogue dialogue."
"Dialogue," not dialogue. "Dialogue."`
const result = string.replace(/"([^"\n\r]*)("|$)/gm, (x,y,z) => z == '"' ? `“${y}”` : `“${y}`)
console.log(result)Details:
" - a double quote([^"\n\r]*) - Group 1: any zero or more chars other than ", CR and LF("|$) - Group 2: " or end of a line (m makes $ match the end of any line).The (x,y,z) => z == '"' ? `“${y}”` : `“${y}` replacement replaces with “ + Group 1 value + ” if Group 2 value is ", else, the replacement is “ + Group 1 value.