I've been learning about prototype in Javascript from a Pluralsight course. And I have some confusion about it.

Here's the example. I have 2 constructors Person and Student:

function Person(firstName, lastName, age) {
  this.firstName = firstName;
  this.lastName = lastName;
  this.age = age;

  this.getFullName = function() {
    console.log(this.firstName + this.lastName)
  }
}

function Student(firstName, lastName, age) {
  this._enrolledCourses = [];

  this.enroll = function (courseId) {
    this._enrolledCourses.push(courseId);
  };

  this.getCourses = function () {
    return this._enrolledCourses;
  };
}

Then create an instance of Student:

let michael = new Student("Michael", "Nguyen", 22);

Now, in the tutorial, it says that in order for michael to inherit everything from Person, there are 2 steps:

• Step 1: Create prototype chain:

Student.prototype = Object.create(Person.prototype);
Student.prototype.constructor = Student;

• Step 2: call Person inside Student:

function Student(firstName, lastName, age) {
  Person.call(this, firstName, lastName, age); <---- this line

  this._enrolledCourses = [];

  this.enroll = function (courseId) {
    this._enrolledCourses.push(courseId);
  };

  this.getCourses = function () {
    f;
    return this._enrolledCourses;
  };
}

However, if I remove step 1 and only follow with step 2, the result remains the same. michael is still able to inherit everything from Person. The thing is, what's the point of step 1 anyway? If I remove step 2 and only get along with step 1, michael won't be able to inherit anything from Person.

FYI, here's the course url: https://app.pluralsight.com/course-player?clipId=f1feb535-bbdd-4255-88e3-ed7079f81e4e