There is a popup (1) that should be called after 15 seconds of being on the page.
But if the user opened some other popup(2), then don't call the first one.
popup(1);
mounted() {
this.openModal();
},
// methods
openModal() {
setTimeout(() => {
this.isModalVisible = true;
}, 15000);
},
How to do it?
Perhaps need to stop setTimeOut?
Maybe something like following snippet:
new Vue({
el: '#demo',
data() {
return {
isModalVisible: false,
isModalOther: false
}
},
methods: {
openModal() {
setTimeout(() => {
if(!this.isModalOther) this.isModalVisible = true;
}, 5000);
},
openOtherModal() {
this.isModalVisible = false
this.isModalOther = true;
},
},
mounted() {
this.openModal();
},
})<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.5.17/vue.js"></script>
<div id="demo">
<div v-if="isModalVisible">popup1</div>
<div v-if="isModalOther">popup2</div>
<button @click="openOtherModal">open popup2</button>
</div>To cancel a timeout, all you need to do is call clearTimeout(TimeoutID);. A timeoutID is a returned by the setTimeout() method automatically, so just save it in a variable
let timer = setTimeout(...);
then, when you call popup(2), just add
this.clearTimeout(timer);
and the first popup won't show