I'm using javascript.
I have a string:
let x = ".175\" x 2.5\" x 144\""; // .175" x 2.5" x 144"
I would like to manipulate the string to return 3 separate variables
var thickness = 0.175
var width = 2.5
var length = 144
I need to change the thickness in the string from .175 to 0.175, here is my attempt:
let x = ".175\" x 2.5\" x 144\"";
let regex = / /g;
let regex2 = /\./i;
let regex3 = /\"/g;
//Do the regex function
const regexFun = () => {
try {
console.log(x);
if (x.charAt(0) == "."){
const fun1 = x.replace(regex2, '0.');
console.log(fun1);
}
else{
const fun1 = x.replace(regex3, '');
console.log(fun1);
}
} catch (err) {
console.log(err.message)
}
}
In the example I gave I can delete the quotes using " but it doesn't seem to work with . How can I go about this? Thanks!
You could match the format of the string with named capture groups.
^(?<thickness>\d*\.?\d+)"\s+x\s+(?<width>\d*\.?\d+)"\s+x\s+(?<length>\d*\.?\d+)"$
The pattern matches:
^ Start of string(?<thickness>\d*\.?\d+) Group thickness match optional digits, optional dot and 1+ digits"\s+x\s+ Match " and an x char between optional whitespace chars(?<width>\d*\.?\d+) Group width with the same digits pattern"\s+x\s+ Match the " and x char(?<length>\d*\.?\d+) Group length with the same digits pattern" Match literally$ End of stringSee the group values on a regex101 demo.
let x = ".175\" x 2.5\" x 144\"";
const regex = /^(?<thickness>\d*\.?\d+)"\s+x\s+(?<width>\d*\.?\d+)"\s+x\s+(?<length>\d*\.?\d+)"$/;
const m = x.match(regex);
if (m) {
const thickness = parseFloat(m.groups.thickness);
const width = parseFloat(m.groups.width);
const length = parseFloat(m.groups.length);
console.log(thickness, width, length);
}Use this Regex
(^|\D)(\.\d+)
( // Begin capture
^ // Beginning of line
| // Or
\D // Any non-digit
) // End capture
( // Begin capture
\. // Decimal point
\d+ // Number
) // End capture
Replace with $10$2
$1 // Contents of the 1st capture
0 // Literal 0
$2 // Contents of the 2nd capture
let x = ".175\" x 2.5\" x 144\"";
console.log(x.replace(/(^|\D)(\.\d+)/g, "$10$2"));As Felix commented, best way may be to extract your numbers using regex first and then parse them as floats:
var x = ".175\" x 2.5\" x 144\""; // .175" x 2.5" x 144"
let numbers = x.match(/(\d*\.)?\d+/g).map(n => parseFloat(n))
var thickness = numbers[0]
var width = numbers[1]
var length = numbers[2]
console.log('thickness: ' + thickness)
console.log('width: ' + width)
console.log('length: ' + length)