i need to make names that start with the letter K appear only in the console
let friends = ["keven", "Khaled", "keiven", 1, 2, "coder", "zein"];
let i = 0;
let counter = 0;
while (i < friends.length) {
console.log(friends[i])
i++
if (friends[i][counter] === friends[i].includes("A")) {
continue;
}
}
You can use the forEach syntax to cycle over your array, and then printing only the elements matching your request (so elements that are string and starts with a "k" letter).
friends.forEach((elem) => {
if(elem.toString().toLowerCase().startsWith("k"))
console.log(elem)
})
const friends = ["keven", "Khaled", "keiven", 1, 2, "coder", "zein"];
for(let friend of friends){
if(String(friend[0]).toLowerCase() === 'k'){
console.log(friend);
}
}