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Filtra el objeto por id y encuentra la puntuación más alta

Estoy tratando de encontrar la sintaxis correcta para ordenar un objeto por id y luego encontrar el puntaje más alto para esa matriz de id. He ordenado el objeto hasta ahora con condicionales y el método sort() pero quiero condensar el objeto al puntaje más alto por lección_id. ¿Qué me estoy perdiendo?

Esto es lo que estoy obteniendo en este punto hasta ahora:

 34: {user: 6, lesson_id: 2, score: 50, complete: true} 35: {user: 6, lesson_id: 1, score: 50, complete: true} 36: {user: 6, lesson_id: 2, score: 50, complete: true} 38: {user: 6, lesson_id: 2, score: 100, complete: true} 39: {user: 6, lesson_id: 2, score: 100, complete: true} 40: {user: 6, lesson_id: 2, score: 100, complete: true}

Pero lo quiero así:

 0: {user: 6, lesson_id: 2, score: 100, complete: true} 1: {user: 6, lesson_id: 1, score: 50, complete: true}

Esto es lo que tengo hasta ahora (Vue3.js):

 mounted() { this.quizArray = response.data; const arrayFilter = this.quizArray; const user_id = this.user_profile[0]["id"]; var newObj = []; var listSort = function () { for (var i = 0; i < arrayFilter.length; i++) { if (arrayFilter[i].student["id"] === user_id) { if (arrayFilter[i].score !== null) { if (arrayFilter[i].complete === true) { arrayFilter.sort((a, b) => a.score - b.score); //not sure about this part .... newObj[i] = { user: arrayFilter[i].student["id"], lesson_id: arrayFilter[i].quiz["lesson_id"], score: arrayFilter[i].score, complete: arrayFilter[i].complete } } } } } }; newObj = this.filteredResults; console.log(this.filteredResults) listSort(); // const highest = this.filteredResults.sort((a, b) => b.score - a.score)[0] // console.log(highest) works but only for one lesson }); },

Aquí está el objeto original:

 35: complete: true quiz: {id: 1, lesson_id: 1, question: 'What is heat transfer?', answer: 'Its is a type of blah', op1: 'Its balahsdd', …} score: 50 student: {user: 'Mark', name: 'Mark', occupation: 'Commissioning Technician', residence: 'Australia', active_id: false, …}
about 4 years ago · Juan Pablo Isaza
2 answers
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Sugeriría utilizar métodos JS para esto, limpiaría el código. Además, no veo el punto de ordenar la matriz, si solo necesita el valor más alto, puede usar el fragmento a continuación. @EDITAR Me olvidé de la agrupación por lección, actualicé la respuesta a continuación

 const userId = this.user_profile[0]["id"]; // get all completed quiz elements for student and with score different than null const quizForStudent = this.quizArray.filter(quiz => quiz.student.id === userId && quiz.complete && quiz.score !== null) // find highest value for all lessons // const highest = quizForStudent.reduce((prev, current) => prev.score > current.score ? prev : current) // group elements per lesson id. this will give result in format // { // 2: [{complete: true, quiz: {lesson_id: 2, ...}, score: 100, student: {...}, {complete: true, quiz: {lesson_id: 2, ...}, score: 100, student: {...}, ...] // 1: [{complete: true, quiz: {lesson_id: 1, ...}, score: 100, student: {...}] // } const scorePerLesson = quizForStudent.reduce((object, current) => { // make sure array exist for given lessonId object[current.quiz.lesson_id] = object[current.quiz.lesson_id] || [] // add array to object object[current.quiz.lesson_id].push(current) return object },{}) // find highest score for each lesson // { // 2: {complete: true, quiz: {lesson_id: 2, ...}, score: 100, student: {...} // 1: {complete: true, quiz: {lesson_id: 1, ...}, score: 100, student: {...} // } const highestScorePerLesson = Object.entries(scorePerLesson).reduce((object, [lessonId, quiz]) => ({ ...object, [lessonId]: quiz.reduce((prev, current) => prev.score > current.score ? prev : current) }), {})

Para obtener el puntaje más alto para una lección determinada (por ejemplo, la lección 2), puede usar

 highestScore[2]

Echa un vistazo en sandbox: enlace

about 4 years ago · Juan Pablo Isaza Report

0

Array.reduce se puede usar para esto:

 const quizArray = [ {user: 6, lesson_id: 2, score: 50, complete: true}, {user: 6, lesson_id: 1, score: 50, complete: true}, {user: 6, lesson_id: 2, score: 50, complete: true}, {user: 6, lesson_id: 2, score: 100, complete: true}, {user: 6, lesson_id: 2, score: 100, complete: true}, {user: 6, lesson_id: 2, score: 100, complete: true} ]; let highScores = Object.values(quizArray .filter(entry => entry.complete) // Only consider completed entries .reduce((highScores, entry) => { // Look up current high score for this lesson let lesson = highScores[entry.lesson_id]; // If there is no score, or the new score is higher, then switch in new entry if (!lesson || (entry.score > lesson.score)) { highScores[entry.lesson_id] = entry; } return highScores; }, {})); console.log(highScores);

about 4 years ago · Juan Pablo Isaza Report
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